If A = diag (2 -5 9), B = diag (1 1 -4) and C = diag (-6 3 4), find 2A + 3B – 5C
If A = diag (2 -5 9), B = diag (1 1 -4) and C = diag (-6 3 4), find 2A + 3B – 5C

Given

\[A\text{ }=\text{ }diag\text{ }\left( 2\text{ }-5\text{ }9 \right),\text{ }\]

\[B\text{ }=\text{ }diag\text{ }\left( 1\text{ }1\text{ }-4 \right)\text{ }\]

\[and\text{ }C\text{ }=\text{ }diag\text{ }\left( -6\text{ }3\text{ }4 \right)\]

Now we have to find \[2A\text{ }+\text{ }3B\text{ }-\text{ }5C\]

Here,

RD Sharma Solutions for Class 12 Maths Chapter 5 Image 173

Now consider \[2A\text{ }+\text{ }3B\text{ }-\text{ }5C\]

RD Sharma Solutions for Class 12 Maths Chapter 5 Image 174