$x=-2$ is one zero of the polynomial $3 x^{2}+4 x+2 k$
Therefore, it will satisfy the above polynomial.
Now, we have
$3(-2)^{2}+4(-2) 1+2 k=0$
$\Rightarrow 12-8+2 k=0$
$\Rightarrow \mathrm{k}=-2$
$x=-2$ is one zero of the polynomial $3 x^{2}+4 x+2 k$
Therefore, it will satisfy the above polynomial.
Now, we have
$3(-2)^{2}+4(-2) 1+2 k=0$
$\Rightarrow 12-8+2 k=0$
$\Rightarrow \mathrm{k}=-2$