$x=1$ is one zero of the polynomial $a x^{2}-3(a-1) x-1$
Therefore, it will satisfy the above polynomial.
Now, we have
$a(1)^{2}-(a-1) 1-1=0$
$\Rightarrow a-3 a+3-1=0$
$\Rightarrow-2 \mathrm{a}=-2$
$\Rightarrow \mathrm{a}=1$
If 1 is a zero of the quadratic polynomial $a x^{2}-3(a-1) x-1$ is 1 , then find the value of a.
If 1 is a zero of the quadratic polynomial $a x^{2}-3(a-1) x-1$ is 1 , then find the value of a.