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(i) If \[\frac{5x+7y}{5u+7v}=\frac{5x-7y}{5u-7v}\], show that \[\frac{x}{y}=\frac{u}{v}\] (ii) \[\frac{8a-5b}{8c-5d}=\frac{8a+5b}{8c+5d}\], prove that \[\frac{a}{b}=\frac{c}{d}\]
(i) If \[\frac{5x+7y}{5u+7v}=\frac{5x-7y}{5u-7v}\], show that \[\frac{x}{y}=\frac{u}{v}\] (ii) \[\frac{8a-5b}{8c-5d}=\frac{8a+5b}{8c+5d}\], prove that \[\frac{a}{b}=\frac{c}{d}\]
Class 10 | Exercise 1 | ICSE | Maths | ML Aggarwal | Ratio and Proportion
(i) If \[\frac{5x+7y}{5u+7v}=\frac{5x-7y}{5u-7v}\], show that \[\frac{x}{y}=\frac{u}{v}\] (ii) \[\frac{8a-5b}{8c-5d}=\frac{8a+5b}{8c+5d}\], prove that \[\frac{a}{b}=\frac{c}{d}\]

Therefore, it is proved.

Therefore, it is proved.

i

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