Zn + 2HCl → ZnCl2 + H2
Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP; atomic mass of Zn = 65.3 u.
Calculation:
1 mole of gas occupies = 22.7l volume at STP
Atomic mass of Zinc (Zn) = 65.3u
65.3g of Zn when reacts with HCl produces 22.7L H2 at STP
Hence,
32.65g of Zinc when reacts with hydrochloric acid will produce 11.35L of H2 at STP.