Given:

The word \[MUMBAI\]

There are \[6\] letters in the word \[MUMBAI\]out of which \[2\] are \[Ms\] and the rest all are distinct.

So let us consider both \[Ms\]together as one letter, the remaining \[5\]letters can be arranged in \[5!\]Ways.

Total number of arrangements \[=\text{ }5!\]

\[=\text{ }5\times 4\times 3\times 2\times 1\]

\[=\text{ }120\]

Hence, a total number of words formed during the arrangement of letters of word \[MUMBAI\] such that all \[Ms\] remains together equals to \[120\]