- 2,4
- 0,4
- 2,3
- 1,3
Solution: 0,4
We can represent 2-iodo-3, 3-dimethyl pentane as follows:
${{H}_{3}}C-CH(I)-C{{(C{{H}_{3}})}_{2}}-C{{H}_{2}}-C{{H}_{3}}$
As we can see that there are zero carbon atoms bound to three other carbon atoms, so there are zero tertiary carbon atoms. A primary carbon is a carbon atom that is bound to only one other carbon atom and as we can see there are four primary carbon atoms.