Answer:
Given,
AP of 7, 10, 13,…
a1 = a = 7
a2 = 10
Common difference,
d = a2 – a1
= 10 – 7
= 3
an = a + (n – 1) d
an = 7 + (n – 1)3
= 7 + 3n – 3
= 3n + 4
Put, an = 43
3n + 4 = 43
3n = 43 – 4
3n = 39
n = 39/3
n = 13
Total 13 terms exists in the A.P.
How many terms are in A.P. 7, 10, 13,…43?
How many terms are in A.P. 7, 10, 13,…43?