Answer : The given no. is 3,5,7,11.
The no. of different products when two or more is taking= the no. of ways of taking the product of two no.+ the no. of ways of taking the product of three no. + the no. of ways of taking the product of four no.
= 4C2 + 4C3 + 4C4
= 6 + 4 + 1
= 11