Given
Harjyot deposited ₹ $27,500$ in a deposit scheme paying $12$%p.a.
Time, t = $3$years
C1 = (P × r × t)/$100$
=$(27,500\times 12\times 1)/100$
= ₹ $3,300$
P1 = $27,500+3,300$
= ₹ $30,800$
C2 = (P × r × t)/$100$
= $(30,800\times 12\times 1)/100$
= ₹ $3,696$
P2 = $30,800+3,696$
= ₹ $34,496$
C3 = (P × r × t)/$100$
= $(34,496\times 12\times 1)/100$
= ₹ $4139.52$
P3 = $4,139.52+34,496$
= ₹ $38,636$
Solution:-
Then, the compound interest received by him = ₹ $3,300$+ ₹$3,696$+ ₹ $4,139.52$
= ₹ $11,135.52$