From a well shuffled deck of 52 cards, one card is drawn. Find the probability that the card drawn will: \[\left( \mathbf{i} \right)\] be a black card. \[\left( \mathbf{ii} \right)\] not be a red card
From a well shuffled deck of 52 cards, one card is drawn. Find the probability that the card drawn will: \[\left( \mathbf{i} \right)\] be a black card. \[\left( \mathbf{ii} \right)\] not be a red card

Solution:

We know that,

Total number of cards \[=\text{ }52\]

So, the total number of outcomes \[=\text{ }52\]

There are \[13\] cards of each type. The cards of heart and diamond are red in colour. Spade and diamond are black. Hence, there are \[26\] red cards and \[26\] black cards.

 

\[\left( i \right)\]Number of black cards in a deck \[=\text{ }26\]

The number of favourable outcomes for the event of drawing a black card \[=\text{ }26\]

Then, probability of drawing a black card \[=\text{ }26/52\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]

 

\[\left( ii \right)\] Number of red cards in a deck \[=\text{ }26\]

Therefore, number of non-red(black) cards \[=\text{ }52\text{ }\text{ }26\text{ }=\text{ }26\]

The number of favourable outcomes for the event of not drawing a red card \[=\text{ }26\]

Then, probability of not drawing a red card \[=\text{ }26/52\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]