a) 4 m

b) 0.5 m

c) λ/2

d) 3 λ/4

e) what is the phase difference between the oscillation of a particle located at x = 100 cm at t = Ts and t = 5s?

Answer:

According to the questions, we have:

y = 2 cos 2 π(10t – 0.0080x + 3.5)

On comparing with the standard equation we get:

a = 2, ω = 20 π, k = 0.016 π and φ = 7 π

a) path difference, p = 4m = 400 cm

Substituting the values, we get phase difference = 6.4 πrad

b) path difference, p = 0.5 m = 50 cm

Substituting the values, we get phase difference = 0.8 π rad

c) path difference, p = λ/2

Substituting the values, we get phase difference = π rad

d) path difference, p = 3 λ/4

Substituting the values, we get phase difference = 98 π rad