India Site

For any Δ ABC show that: c-b cos A / b – c cos A = cos B / cos C

 

Considering L.H.S :

Getting terms c – b cos A and b – c cos A from projection formula

Using projection formula,

\[c\text{ }=\text{ }a\text{ }cos\text{ }B\text{ }+\text{ }b\text{ }cos\text{ }A\]

\[c\text{ }\text{ }b\text{ }cos\text{ }A\text{ }=\text{ }a\text{ }cos\text{ }B\text{ }\ldots .\text{ }\left( i \right)\]

And,

\[b\text{ }=\text{ }c\text{ }cos\text{ }A\text{ }+\text{ }a\text{ }cos\text{ }C\]

\[b\text{ }\text{ }c\text{ }cos\text{ }A\text{ }=\text{ }a\text{ }cos\text{ }C\text{ }\ldots .\text{ }\left( ii \right)\]

On dividing equation (i) by (ii),

\[=\text{ }RHS\]

Hence Proved.