\[\mathbf{715},\text{ }\mathbf{724},\text{ }\mathbf{725},\text{ }\mathbf{710},\text{ }\mathbf{729},\text{ }\mathbf{745},\text{ }\mathbf{694},\text{ }\mathbf{699},\text{ }\mathbf{696},\text{ }\mathbf{712},\text{ }\mathbf{734},\text{ }\mathbf{728},\text{ }\mathbf{716},\text{ }\mathbf{705},\text{ }\mathbf{719}.\]

Solution:

Arranging the given data in ascending order, we have

\[694,\text{ }696,\text{ }699,\text{ }705,\text{ }710,\text{ }712,\text{ }715,\text{ }716,\text{ }719,\text{ }721,\text{ }725,\text{ }728,\text{ }729,\text{ }734,\text{ }745\]

As the number of terms is an old number i.e., \[N\text{ }=\text{ }15\]

We use the following procedure to find the median.

Median \[=\text{ }\left( N\text{ }+\text{ }1 \right)/2{{~}^{th~}}\] term

\[=\text{ }\left( 15\text{ }+\text{ }1 \right)/2{{~}^{th~}}\] term

=\[~{{8}^{th}}~\]term

So, the\[~{{8}^{th}}~\]term in the arranged order of the given data should be the median.

Therefore, \[716\]is the median of the data.