To find the zeroes of the quadratic polynomial we will equate $\mathrm{f}(\mathrm{x})$ to 0
Hence, the zeroes of the quadratic polynomial $f(x)=6 x^{2}-3$ are $\frac{1}{\sqrt{2}},-\frac{1}{\sqrt{2}}$.
To find the zeroes of the quadratic polynomial we will equate $\mathrm{f}(\mathrm{x})$ to 0
Hence, the zeroes of the quadratic polynomial $f(x)=6 x^{2}-3$ are $\frac{1}{\sqrt{2}},-\frac{1}{\sqrt{2}}$.