Find the slope and y-intercept of the following lines:(iii) 3x + 5y + 7 = 0 (iv) x/3 + y/4 = 1

(iii) 3x + 5y + 7 = 0

5y = -3x – 7

⇒ y = (-3/5) x + (-7/5)

Hence, slope = -3/5 and y-intercept = -7/5

(iv) x/3 + y/4 = 1

(4x + 3y)/ 12 = 1

4x + 3y = 12

3y = -4x + 12

⇒ y = (-4/3) x + 4

Hence, slope = -4/3 and y-intercept = 4