Find the simplest form of \[(i)\frac{69}{92}(ii)\frac{473}{645}\]

Answers:

(i) Prime factorization of 69 and 92:

69 = 3 × 23

92 = 2² × 23

$\eqalign{

& \frac{{69}}{{92}} = \frac{{3 \times 23}}{{{2^2} \times 23}}  \cr

&  =  > \frac{3}{{{2^2}}}  \cr

&  =  > \frac{3}{4} \cr} $

(ii) Prime factorization of 473 and 645:

473 = 11 × 43

645 = 3 × 5 × 43

$$$\eqalign{

& \frac{{473}}{{645}} = \frac{{11 \times 43}}{{3 \times 5 \times 43}}  \cr

&  =  > \frac{{11}}{{15}} \cr} $