Solution:
Let’s take $y=x^{2}+3 x+2$
Now the first derivative:
$\frac{d y}{d x}=2 x+3 \times 1+0=2 x+3$
The second derivative:
$\frac{d^{2} y}{d x^{2}}=\frac{d}{d x}\left(\frac{d y}{d x}\right)=2 \times 1+0=2$
Solution:
Let’s take $y=x^{2}+3 x+2$
Now the first derivative:
$\frac{d y}{d x}=2 x+3 \times 1+0=2 x+3$
The second derivative:
$\frac{d^{2} y}{d x^{2}}=\frac{d}{d x}\left(\frac{d y}{d x}\right)=2 \times 1+0=2$