$\begin{array}{l}
4-11 x=3 x^{2} \\
\Rightarrow 3 x^{2}+11 x-4=0 \\
\Rightarrow 3 x^{2}+12 x-x-4=0 \\
\Rightarrow 3 x(x+4)-1(x+4)=0 \\
\Rightarrow(x+4)(3 x-1)=0 \\
\Rightarrow x+4=0 \text { or } 3 x-1=0 \\
\Rightarrow x=-4 \text { or } x=\frac{1}{3}
\end{array}$

Hence, the roots of the equation are $-4$ and $\frac{1}{3}$.