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Find the reciprocal ratio of the following:(i) $17/45:51/27$(ii) $1/45:1/54$

The ratio is used for comparing two quantities of the sane kind.

The ratio formula for two numbers says a and b is given by a:b or a/b. When two or more such ratios are equal, they are said to be in proportion.

The concept of ratio and proportion is majorly based on ratios and fractions.  

Solution:

Given ratio, $17/45:51?27$

The reciprocal of the given ratio is $45/17:51/27$

$=\left( 45/17 \right)\times \left( 51/27 \right)$

$=\left( 45/1 \right)\times \left( 3/27 \right)$

$=\left( 45/1 \right)\times \left( 1/9 \right)$

$=5/1$ Therefore, reciprocal of the ratio is $5:1$

Solution:

Given ratio, $1/45:1/54$

The reciprocal of the given ratio is $45/1:54/1$

$=45/1:54/1$

$=45:54$

$=45/54$

$=5/6$

Therefore, reciprocal of the ratio is $5:6$