Given equation,
Hence, the real solutions of the given trigonometric equation are \[0\] and \[-1\].
Find the real solution of the equation : $$ $\tan \hat{\ }-1\sqrt{x(x+1)}+\sin \hat{\ }-1\sqrt{x\hat{\ }2+x+1}=\pi /2$
Find the real solution of the equation : $$ $\tan \hat{\ }-1\sqrt{x(x+1)}+\sin \hat{\ }-1\sqrt{x\hat{\ }2+x+1}=\pi /2$