Let’s P divide A$(-3,10)$ and B$(6,-8)$ in the ratio of k:$1$
Given that the coordinates of P as ($-1$,y)
Now, by using the section formula for x – coordinate we have
$-1=6k–3/k+1$
$-(k+1)=6k–3$
$7k=2$
$k=2/7$
Therefore, the point P divides AB in the ratio of $2:7$
Using value of k, to find the y-coordinate we have
y $=(-8k+10)/(k+1)$
y $=(-8(2/7)+10)/(2/7+1)$
y$=-16+70/2+7=54/9$
y $=6$
Hence, the y-coordinate of P is $6$