Find the quadratic polynomial, sum of whose zeroes is $\sqrt{2}$ and their product is $\left(\frac{1}{3}\right)$.

Quadratic equation can be found  if we know the sum of the roots and product of the roots by using the formula:

$\mathrm{x}^{2}-($ Sum of the roots) $\mathrm{x}+$ Product of roots $=0$

$\Rightarrow x^{2}-\sqrt{2} x+\frac{1}{3}=0$

$\Rightarrow 3 x^{2}-3 \sqrt{2} x+1=0$