Solution:-
To find mean deviation, first we have to find mean\[(\overline{x})\]
\[\overline{x}=\frac{1}{10}\sum\limits_{i=1}^{10}{{{x}_{i}}}=\frac{500}{10}=50\]
Determine the respective values of the deviations from mean,
i.e., \[{{x}_{i}}-\overline{x}\] are, \[50-38=-12\], \[50-70=-20\], \[50-48=2\], \[50-40=10\], \[50-42=8\],
\[50-55=-5\], \[50-63=-13\], \[50-46=4\], \[50-54=-4\], \[50-44=6\]
The deviations are
\[-12,20,-2,-10,-8,5,13,-4,4,-6\]
Therefore, the absolute values of the deviations,
\[12,20,2,10,8,5,13,4,4,6\]
\[\sum\limits_{i=1}^{10}{\left| {{x}_{i}}-\overline{x} \right|}=84\]
We know that Mean deviation = sum of deviations/ number of observations
= \[84/10\]
= \[8.4\]
Hence, the mean deviation for the given data is \[8.4\]