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Find the fourth proportional to (iii) \[\mathbf{1}.\mathbf{5},\text{ }\mathbf{2}.\mathbf{5},\text{ }\mathbf{4}.\mathbf{5}\] (iv) \[\mathbf{9}.\mathbf{6}\text{ }\mathbf{kg},\text{ }\mathbf{7}.\mathbf{2}\text{ }\mathbf{kg},\text{ }\mathbf{28}.\mathbf{8}\text{ }\mathbf{kg}\]

(iii) \[1.5,\text{ }2.5,\text{ }4.5\]

Consider x as the fourth proportional to \[1.5,\text{ }2.5,\text{ }4.5\]

\[1.5:\text{ }2.5\text{ }::\text{ }4.5:\text{ }x\]

We can write it as

\[1.5\text{ }\times \text{ }x\text{ }=\text{ }2.5\text{ }\times \text{ }4.5\]

So we get

\[\begin{array}{*{35}{l}}

x\text{ }=\text{ }\left( 2.5\text{ }\times \text{ }4.5 \right)/\text{ }1.5  \\

x\text{ }=\text{ }7.5  \\

\end{array}\]

(iv) \[9.6\text{ }kg,\text{ }7.2\text{ }kg,\text{ }28.8\text{ }kg\]

Consider x as the fourth proportional to \[9.6\text{ }kg,\text{ }7.2\text{ }kg,\text{ }28.8\text{ }kg\]

\[9.6:\text{ }7.2\text{ }::\text{ }28.8:\text{ }x\]

We can write it as

\[9.6\text{ }\times \text{ }x\text{ }=\text{ }7.2\text{ }\times \text{ }28.8\]

So we get

\[\begin{array}{*{35}{l}}

x\text{ }=\text{ }\left( 7.2\text{ }\times \text{ }28.8 \right)/\text{ }9.6  \\

x\text{ }=\text{ }21.6  \\

\end{array}\]