Solution:

Let the line containing the point P (3, 2) pass through x-axis at A (x, 0) and y-axis at B (0, y)

OA = OB

Thus, x = y

Now, the slope of the line (m) = y₂ – y₁/ x₂ – x₁

= 0 – y/ x – 0

= -x/x = -1

Hence, the equation of the line will be

y – y₁ = m (x – x₁)

y – 2 = -1 (x – 3)

y – 2 = -x + 3

⇒ x + y – 5 = 0