Solution:
Given line: 3x – 2y = -4
Slope (m1) is given by
2y = 3x + 4
y = (3/2) x + 2
So, m1 = 3/2
Now, the slope of the line parallel to the given line will have the same slope as 3/2 = m
And the line passes through point (0, 3)
Thus, the equation of the required line is given by
y = mx + c
y = (3/2) x + 3
2y = 3x + 6
3x – 2y + 6 = 0