Find the equation of a straight line whose inclination is 60° and which passes through the point (0, – 3).

Solution:

Given,

Inclination of a straight line is 60^o

So, the slope = tan 60^o = √3 = m

And, the equation of line passes through the point (0, -3) = (x₁, y₁)

Hence, the equation of line is given by

y – y₁ = m (x – x₁)

y + 3 = √3 (x – 0)

y + 3 = √3x

√3x – y – 3 = 0

Thus, the line equation is √3x – y – 3 = 0.