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Find the duplicate ratio of the following:(iii) $2/3:4/9$(iv) $\left( a+b \right):\left( {{a}^{2}}-{{b}^{2}} \right)$

The ratio is used for comparing two quantities of the sane kind.

The ratio formula for two numbers says a and b is given by a:b or a/b. When two or more such ratios are equal, they are said to be in proportion.

The concept of ratio and proportion is majorly based on ratios and fractions.  

Solution:

Given, $2/3:4/9$

$={{\left( 2/3 \right)}^{2}}:{{\left( 4/9 \right)}^{2}}$

$=4/9:16/81$

$=\left( 4/9 \right)\times \left( 81/16 \right)$

$=\left( 4\times 81 \right)/\left( 9\times 16 \right)$

$=\left( 1\times 9 \right)/\left( 1\times 4 \right)$

$=9/4$

Therefore, duplicate ratio = 9: 4

Solution:

Given,

 $\left( a+b \right):\left( {{a}^{2}}-{{b}^{2}} \right)$

$={{\left( a+b \right)}^{2}}:{{\left( {{a}^{2}}-{{b}^{2}} \right)}^{2}}$

$={{\left( a+b \right)}^{2}}/\left( {{\left( a+b \right)}^{2}}{{\left( a-b \right)}^{2}} \right)$

$=1/{{\left( a-b \right)}^{2}}$

Therefore, duplicate ratio $=1:{{\left( a-b \right)}^{2}}$