The angle between A and B = 0o
Therefore, the emf is Bvd.
-LdI(t)/dt + Bvd = IR
LdI(t)/dt + RI (t) = Bvd
Solving the equation, we get
I = Bvd/R [1-e-Rt/2]
The angle between A and B = 0o
Therefore, the emf is Bvd.
-LdI(t)/dt + Bvd = IR
LdI(t)/dt + RI (t) = Bvd
Solving the equation, we get
I = Bvd/R [1-e-Rt/2]