solution
Given Radius of the circle = r = \[5\] cm
Given Arc length of the sector = l = \[3.5\] cm
Let us consider the central angle (in radians) be \[\theta \].
As we know that Arc length = Radius × Central angle (in radians)
From Central angle (\[\theta \])= Arc length / Radius = l / r = \[3.5/5\] = \[0.7\] radians
As we know that the Area of the sector = \[(1/2)\times {{r}^{2}}\theta \] = \[(1/2)\times 25\times 0.7\] = \[8.75\] \[c{{m}^{2}}\]
Therefore, the required area of the sector of a circle is \[8.75\] \[c{{m}^{2}}\].