Find the 10th term of the G.P. :
Find the 10th term of the G.P. :

Selina Solutions Concise Class 10 Maths Chapter 11 ex. 11(A) - 2

Answer

It can be written as

\[12,\text{ }4,\text{ }4/3,\text{ }\ldots ..\]

It’s seen that, the initial term is \[\left( a \right)\text{ }=\text{ }12\]

What’s more, typical ratio \[\left( r \right)\text{ }=\text{ }\left( 4 \right)/\text{ }\left( 12 \right)\text{ }=\text{ }1/3\]

We realize that, the overall term is

\[{{t}_{n}}~=\text{ }a{{r}^{n\text{ }\text{ }1}}\]

So,

\[{{t}_{10}}~=\text{ }\left( 12 \right){{\left( 1/3 \right)}^{10\text{ }\text{ }1}}~=\text{ }\left( 12 \right){{\left( 1/3 \right)}^{9~}}\]

\[=\text{ }12\text{ }x\text{ }1/\left( 19683 \right)\text{ }=\text{ }4/\text{ }6561\]