Let’s P$(5,-6)$ and Q$(-1,-4)$ be the given points.

Let’s the y-axis divide the line segment PQ in the ratio k: $1$

Now, by using section formula for the x-coordinate (as it’s zero)

Now we have

$\frac{-K+5}{K+1}=0$

$-K+5=0$

$K=5$

Therefore, the ratio in which the y-axis divides the given $2$ points is $5:1$

So , for finding the coordinates of the point of division

Putting k = 5, we get

$\left( \frac{-5+5}{5+1},\frac{-4\times 5-6}{5+1} \right)=\left( 0,\frac{13}{3} \right)$

Therefore, the coordinates of the point of division are $(0,-13/3)$