Find angles between the lines √3x + y = 1 and x + √3y = 1.
Find angles between the lines √3x + y = 1 and x + √3y = 1.

Given:

 

The lines are \[\surd \mathbf{3x}\text{ }+\text{ }\mathbf{y}\text{ }=\text{ }\mathbf{1}\text{ }\mathbf{and}\text{ }\mathbf{x}\text{ }+\text{ }\surd \mathbf{3y}\text{ }=\text{ }\mathbf{1}\]

Along these lines, \[\mathbf{y}\text{ }=\text{ }-\text{ }\surd \mathbf{3x}\text{ }+\text{ }\mathbf{1}\text{ }\ldots \text{ }\left( \mathbf{1} \right)\] and

 

\[\mathbf{y}\text{ }=\text{ }-\text{ }\mathbf{1}/\surd \mathbf{3x}\text{ }+\text{ }\mathbf{1}/\surd \mathbf{3}\text{ }\ldots \text{ }.\text{ }\left( \mathbf{2} \right)\]

Slant of line (1) is m1 = – √3, while the incline of line (2) is \[\mathbf{m2}\text{ }=\text{ }-\text{ }\mathbf{1}/\surd \mathbf{3}\]

Let θ be the point between two lines

 

Along these lines,

NCERT Solutions for Class 11 Maths Chapter 10 – Straight Lines image - 37

\[\mathbf{\theta }\text{ }=\text{ }\mathbf{30}{}^\circ \]

The point between the given lines is either 30° or \[\mathbf{180}{}^\circ -\mathbf{30}{}^\circ \text{ }=\text{ }\mathbf{150}{}^\circ \]