Find $\alpha, \beta$ are the zeros of polynomial $\alpha+\beta=6$ and $\alpha \beta=4$ then write the polynomial.

If the zeroes of the quadratic polynomial are $\alpha$ and $\beta$ then the quadratic polynomial can be found as $\mathrm{x}^{2}-(\alpha+\beta) \mathrm{x}+\alpha \beta$

$\ldots \ldots(1)$

Substituting the values in (1), we get

$x^{2}-6 x+4$