Now,
if f(t) is discontinuous, then \[2-\text{ }\text{ }x\text{ }=\text{ }0\Rightarrow x\text{ }=\text{ }2\] And, \[2x-\text{ }\text{ }1\text{ }=\text{ }0\Rightarrow x\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]
hence, the points of discontinuity for the function are \[2\text{ }and\text{ }{\scriptscriptstyle 1\!/\!{ }_2}.\]