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Figure shows a uniform metre rule of weight W supported on a fulcrum at the 60 cm mark by applying the effort E at the 90 cm mark.
Figure shows a uniform metre rule of weight W supported on a fulcrum at the 60 cm mark by applying the effort E at the 90 cm mark.
Class 10 | ICSE | Machines | Physics | Selina
Figure shows a uniform metre rule of weight W supported on a fulcrum at the 60 cm mark by applying the effort E at the 90 cm mark.

(a) State with reasons whether the weight W of the rule is greater than, less than or equal to the effort E.

 (b) Find the mechanical advantage in an ideal case.

Solutions:

(a) The scale’s weight W is greater than E.
The arm on the side of effort E is 30 cm long, and the arm on the side of the scale weight is 10 cm long. To balance the scale, the weight W of the scale must be greater than the effort E.

(b) We know that the expression for mechanical advantage is as follows –

M.A. = Effort arm / Load arm

We have, Effort arm = 30 cm and the Load arm = 10 cm

Therefore upon substituting values, we get = M.A. = 30 / 10

M.A. = 3

i

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