Draw a straight line AB of $9 cm$. Draw the locus of all points which are equidistant from A and B. You need to Prove your statement.
Draw a straight line AB of $9 cm$. Draw the locus of all points which are equidistant from A and B. You need to Prove your statement.

Steps of  construction:

(1) Draw a line segment AB of the length $9 cm$.

(2) Then draw perpendicular bisector PQ of line segment AB. So PQ is the required locus.

Proof:

(a)Let us take  any point on PQ i.e. C.

(b) Now, let us  join CA and CB.

Since, C lies on the perpendicular bisector of line segment AB.

Hence, C is equidistant from A and B.

Therefore, we can say that  $CA = CB$ Hence, it is proved that perpendicular bisector of  line segment AB is the locus of all points which are equidistant from A and B.