According to ques,
Length of
\[AB\text{ }=\text{ }7\text{ }cm\]
(base)
Area of triangle PAB
\[=\text{ }14\text{ }c{{m}^{2}}\]
We know that
Height = (area × 2)/ base
Substituting the values
\[\begin{array}{*{35}{l}}
=\text{ }\left( 14\text{ }\times \text{ }2 \right)/\text{ }7 \\
=\text{ }4\text{ }cm \\
\end{array}\]
Construct a line XY which is parallel to AB and at a distance of 4 cm.
Take any point P on XY
Now join PA and PB
Area of triangle PAB
\[=\text{ }14\text{ }c{{m}^{2}}\]
hence,
locus of P is the line XY which is parallel to AB at a distance of 4 cm.