Divide 64 into two parts such that the sum of the cubes of two parts is minimum.
Divide 64 into two parts such that the sum of the cubes of two parts is minimum.

Let the two positive numbers be $a$ and $b$

Given \[a\text{ }+\text{ }b\text{ }=\text{ }64\text{ }\ldots \text{ }\left( 1 \right)\]

We have, \[{{a}^{3}}~+\text{ }{{b}^{3}}\] is minima

Assume, \[S\text{ }=\text{ }{{a}^{3}}~+\text{ }{{b}^{3}}\]

(From equation 1)

\[S\text{ }=\text{ }{{a}^{3}}~+\text{ }{{\left( 64\text{ }-\text{ }a \right)}^{3}}\]

RD Sharma Solutions for Class 12 Maths Chapter 18 Maxima and Minima Image 15