(i) Given
\[{{a}_{i\text{ }j}}~=\text{ }{{\left( i\text{ }\text{ }2j \right)}^{2~}}/2\]
Let
\[A\text{ }=\text{ }{{[{{a}_{i\text{ }j}}]}_{2\times 2}}\]
So, the elements in a
\[2\text{ }\times \text{ }2\]
matrix are
\[{{a}_{11}},\text{ }{{a}_{12}},\text{ }{{a}_{21}},\text{ }{{a}_{22}}\]
\[{{a}_{11}}~=\]
\[{{a}_{12}}~=\]
\[{{a}_{21}}~=\]
\[{{a}_{22}}~=\]
Substituting these values in matrix A we get,
(ii) Given
\[{{a}_{i\text{ }j}}~=\text{ }{{\left( 2i\text{ }+\text{ }j \right)}^{2~}}/2\]
Let
\[A\text{ }=\text{ }{{[{{a}_{i\text{ }j}}]}_{2\times 2}}\]
So, the elements in a
\[2\text{ }\times \text{ }2\]
matrix are
\[{{a}_{11}},\text{ }{{a}_{12}},\text{ }{{a}_{21}},\text{ }{{a}_{22}}\]
\[{{a}_{11}}~=\]
\[{{a}_{12}}~=\]
\[{{a}_{21}}~=\]
\[{{a}_{22}}~=\]
Substituting these values in matrix A we get,
