Consider the junction diode as ideal. The value of current flowing through AB is:
A $\quad 0 \mathrm{~A}$
B $\quad 10^{-2} \mathrm{~A}$
C $\quad 10^{-1} \mathrm{~A}$
D $\quad 10^{-3} \mathrm{~A}$

Correct Option B

Solution:

In this case the diode is forward biased so it offers no resistance, thus evaluating,

$V_{A}-i R=V_{B}$

$V_{A}-V_{B}=i R$

$i=\frac{V_{A}-V_{B}}{R}$

$i=\frac{4-(-6)}{1000}=\frac{10}{1000}=10^{-2} \mathrm{~A}$