Correct Option B
Solution:
In this case the diode is forward biased so it offers no resistance, thus evaluating,
$V_{A}-i R=V_{B}$
$V_{A}-V_{B}=i R$
$i=\frac{V_{A}-V_{B}}{R}$
$i=\frac{4-(-6)}{1000}=\frac{10}{1000}=10^{-2} \mathrm{~A}$
Correct Option B
Solution:
In this case the diode is forward biased so it offers no resistance, thus evaluating,
$V_{A}-i R=V_{B}$
$V_{A}-V_{B}=i R$
$i=\frac{V_{A}-V_{B}}{R}$
$i=\frac{4-(-6)}{1000}=\frac{10}{1000}=10^{-2} \mathrm{~A}$