Because the rate of reaction of compound ‘A’ (C4H9Br) with aqueous KOH is solely determined by the concentration of compound ‘A,’ the reaction happens via the SN1 mechanism, and product ‘A’ is 2-Bromo-2-methylpropane.
(ii) Because of the SN2 reaction, compound ‘B’ will undergo configuration inversion and produce an inverted product.