solution:
R = {(a, b) : b = a + 1}
R = {(1, 2), (2, 3), (3, 4), (4, 5), (5, 6)}
At the point when b = a, a = a + 1: which is bogus, So R isn’t reflexive.
In the event that (a, b) = (b,a), b = a+1 and a =b+1: Which is bogus, so R isn’t symmetric.
Presently, in the event that (a, b), (b,c) and (a, c) has a place with R
b = a+1 and c =b+1 which infers c = a + 2: Which is bogus, so R isn’t transitive. Consequently, R is neither reflexive, nor symmetric and nor transitive.