Solution:
In the above mentioned given series, A.P. 11, 8, 5, 2..
The first term, a = 11
The common difference, d = a2−a1 = 8−11 = −3
Let −150 be the nth term of this A.P.
As we all know, for an A.P.,
an = a+(n−1)d
-150 = 11+(n -1)(-3)
-150 = 11-3n +3
-164 = -3n
n = 164/3
Clearly we see that, n is not an integer but a fraction.
Therefore, – 150 isn’t a term of this A.P.