Let take the cost of the entry ticket initially and at present to be 10x and 13x respectively. And let the number of visitors initially and at present be 6y and 5y respectively. Therefore,...
The bus fare between two cities is increased in the ratio 7: 9. Find the increase in the fare, if: (i) the original fare is Rs 245; (ii) the increased fare is Rs 207.
From the question we have, Increased (new) bus fare = (9/7) x original bus fare (i) Increased (new) bus fare= \[=~9/7\text{ }*\text{ }Rs\text{ }245\text{ }=\text{ }Rs\text{ }315\] Thus, the increase...
The work done by (x – 2) men in (4x + 1) days and the work done by (4x + 1) men in (2x – 3) days are in the ratio 3: 8. Find the value of x.
On assuming that the same amount of work is done one day by all the men and one day work of each man = 1 units, we get Amount of work done by (x – 2) men in (4x + 1) days = Amount of work done by (x...
The monthly pocket money of Ravi and Sanjeev are in the ratio 5: 7. Their expenditures are in the ratio 3: 5. If each saves Rs. 80 every month, find their monthly pocket money.
The pocket money of Ravi and Sanjeev are in the ratio 5: 7 Thus, we assume the pocket money of Ravi as 5k and that of Sanjeev as 7k. Also, The expenditure of Ravi and Snajeev are in the ratio 3: 5...
A school has 630 students. The ratio of the number of boys to the number of girls is 3: 2. This ratio changes to 7: 5 after the admission of 90 new students. Find the number of newly admitted boys.
Let the number of boys be 3x. Then, the number of girls = 2x \[\begin{array}{*{35}{l}} \Rightarrow \text{ }3x\text{ }+\text{ }2x\text{ }=\text{ }630 \\ 5x\text{ }=\text{ }630 \\ x\text{ }=\text{...
Divide Rs 1290 into A, B and C such that A is 2/5 of B and B: C = 4: 3.
B: C = 4: 3 so, B/C = 4/3 ⇒ C = (3/4) B And, A = (2/5) B Since, \[\begin{array}{*{35}{l}} A\text{ }+\text{ }B\text{ }+\text{ }C\text{ }=\text{ }Rs\text{ }1290 \\ \left( 2/5 \right)\text{ } B\text{...
If the ratio between 8 and 11 is the same as the ratio of 2x – y to x + 2y, find the value of 7x/ 9y.
\[\left( 2x\text{ }-\text{ }y \right)/\text{ }\left( x\text{ }+\text{ }2y \right)\text{ }=\text{ }8/11\] On cross multiplying, we get \[\begin{array}{*{35}{l}} 11\left( 2x\text{ }-\text{ }y...
Find x/y; when x^2 + 6y^2 = 5xy
Given, \[{{x}^{2}}~+\text{ }6{{y}^{2}}~=\text{ }5xy\] Dividing by y2 both side, we have Let \[\begin{array}{*{35}{l}} x/y\text{ }=\text{ }a \\ =>\text{ }{{a}^{2}}~\text{ }-5a\text{ }+\text{...
SOLVE:
SOLUTION: Since, \[\begin{array}{*{35}{l}} 3\left( m\text{ }+\text{ }n \right)\text{ }=\text{ }2\left( m\text{ }+\text{ }3n \right) \\ 3m\text{ }+\text{ }3n\text{ }=\text{ }2m\text{ }+\text{ }6n ...
What quantity must be subtracted from each term of the ratio 9: 17 to make it equal to 1: 3?
Let x be subtracted from each term of the ratio 9: 17. 27 – 3x = 17 – x 10 = 2x x = 5 Therefore, the required number that should be subtracted is 5.
Find the number which bears the same ratio to 7/33 that 8/21 does to 4/9.
Let the required number to be x/y Since, Ratio of \[8/21\text{ }to\text{ }4/9\text{ }=\text{ }\left( 8/21 \right)/\text{ }\left( 4/9 \right)\text{ }=\text{ }\left( 8/21 \right)\text{ }x\text{...
If (a – b): (a + b) = 1: 11, find the ratio (5a + 4b + 15): (5a – 4b + 3).
Since, \[\begin{array}{*{35}{l}} \left( a\text{ }\text{ }-b \right)/\text{ }\left( a\text{ }+\text{ }b \right)\text{ }=\text{ }1/\text{ }11 \\ 11a\text{ }\text{ }-11b\text{ }=\text{ }a\text{...
If a: b = 3: 8, find the value of 4a + 3b/ 6a – b.
Since, a: b = 3: 8 Therefore, a/b = 3/8
If x: y = 4: 7, find the value of (3x + 2y): (5x + y).
Since, x: y = 4: 7 Therefore, x/y = 4/7
If a: b = 5: 3, find: 5a – 3b/ 5a + 3b
Since, a: b = 5: 3 Therefore, a/b = 5/3 Now,