Given condition, \[x4\text{ }\text{ }10x2\text{ }+\text{ }9\text{ }=\text{ }0\] \[x4\text{ }\text{ }x2\text{ }\text{ }9x2+\text{ }9\text{ }=\text{ }0\] \[x2\left( x2\text{ }\text{ }1 \right)\text{...
Solve: x4 – 2×2 – 3 = 0
Given condition, \[x4\text{ }\text{ }2x2\text{ }\text{ }3\text{ }=\text{ }0\] \[x4\text{ }\text{ }3x2\text{ }+\text{ }x2\text{ }\text{ }3\text{ }=\text{ }0\] \[x2\left( x2\text{ }\text{ }3...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places: (iii) 2×2 + 11x + 4 = 0
(iii) Given condition, \[2x2\text{ }+\text{ }11x\text{ }+\text{ }4\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }2,\text{ }b\text{ }=\text{ }11\text{ }and\text{ }c\text{ }=\text{ }4\] Thusly,...
Solve each of the following equations for x and give, in each case, your answer correct to 3 decimal places: (i) 3×2 – 12x – 1 = 0 (ii) x2 – 16 x +6 = 0
(i) Given condition, \[3x2\text{ }\text{ }12x\text{ }\text{ }1\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }3,\text{ }b\text{ }=\text{ }-\text{ }12\text{ }and\text{ }c\text{ }=\text{ }-\text{ }1\]...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places: x2 – 5x – 10 = 0
Given condition, \[x2\text{ }\text{ }5x\text{ }\text{ }10\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }-\text{ }5\text{ }and\text{ }c\text{ }=\text{ }-\text{ }10\] Thus,...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places: x2 – 3x – 9 = 0
Given condition, \[x2\text{ }\text{ }3x\text{ }\text{ }9\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }-\text{ }3\text{ }and\text{ }c\text{ }=\text{ }-\text{ }9\]...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places: 4×2 – 5x – 3 = 0
Given condition, \[4x2\text{ }\text{ }5x\text{ }\text{ }3\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }4,\text{ }b\text{ }=\text{ }-\text{ }5\text{ }and\text{ }c\text{ }=\text{ }-\text{ }3\] In...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places : 4x + 6/x + 13 = 0
Given condition, \[4x\text{ }+\text{ }6/x\text{ }+\text{ }13\text{ }=\text{ }0\] Increasing by x the two sides, we get \[4x2\text{ }+\text{ }13x\text{ }+\text{ }6\text{ }=\text{ }0\] Here, \[a\text{...
Solve each of the following equation for x and give, in each case, your answer correct to 2 decimal places: 2×2 – 10x + 5 = 0
Given condition, \[2x2\text{ }\text{ }10x\text{ }+\text{ }5\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }2,\text{ }b\text{ }=\text{ }-\text{ }10\text{ }and\text{ }c\text{ }=\text{ }5\]...
Solve each of the following equations for x and give, in each case, your answer correct to one decimal place: (i) x2 – 8x +5 = 0 (ii) 5×2 + 10x – 3 = 0
(i) \[x2\text{ }\text{ }8x\text{ }+\text{ }5\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }-\text{ }8\text{ }and\text{ }c\text{ }=\text{ }5\] By quadratic...
Solve equations using formula:
From the given condition, \[10x2\text{ }\text{ }60x\text{ }+\text{ }80\text{ }=\text{ }6x2\text{ }\text{ }30x\text{ }+\text{ }30\] \[4x2\text{ }\text{ }30x\text{ }+\text{ }50\text{ }=\text{ }0\]...
Solve equations using formula: 2x/ x – 4 + (2x – 5)/(x – 3) =
2x/ x – 4 + (2x – 5)/(x – 3) = Given condition, \[2x/x\text{ }\text{ }4\text{ }+\text{ }\left( 2x\text{ }\text{ }5 \right)/\left( x\text{ }\text{ }3 \right)\] \[25x2\text{ }\text{ }175x\text{...
Solve equations using formula: √6×2 – 4x – 2√6 = 0
Given condition, \[\surd 6x2\text{ }\text{ }4x\text{ }\text{ }2\surd 6\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }\surd 6,\text{ }b\text{ }=\text{ }-\text{ }4\text{ }and\text{ }c\text{ }=\text{...
Solve equations using formula: 2x + 3/ x + 3 = x + 4/ x + 2
Given condition, \[2x\text{ }+\text{ }3/x\text{ }+\text{ }3\text{ }=\text{ }x\text{ }+\text{ }4/x\text{ }+\text{ }2\] On cross-duplicating, we have \[\left( 2x\text{ }+\text{ }3 \right)\text{...
Solve equations using formula: 4/x – 3 = 5/ (2x + 3)
Given condition, \[4/x\text{ }\text{ }3\text{ }=\text{ }5/\left( 2x\text{ }+\text{ }3 \right)\] \[\left( 4\text{ }\text{ }3x \right)/x\text{ }=\text{ }5/\left( 2x\text{ }+\text{ }3 \right)\] On...
Solve equations using formula: x2 – 6 = 2 √2 x
Given condition, \[x2\text{ }\text{ }6\text{ }=\text{ }2\text{ }\surd 2\text{ }x\] \[x2\text{ }\text{ }2\surd 2\text{ }x\text{ }\text{ }6\text{ }=\text{ }0\] Here, \[a\text{ }=\text{...
Solve equations using formula: 1/15 x2 + 5/3 = 2/3 x
Given condition, \[1/15\text{ }x2\text{ }+\text{ }5/3\text{ }=\text{ }2/3\text{ }x\] \[1/15\text{ }x2\text{ }\text{ }2/3\text{ }x\text{ }+\text{ }5/3\text{ }=\text{ }0\] Increasing by 15 on...
Solve equations using formula: 2/3 x = -1/6 x2 – 1/3
Given condition, \[2/3\text{ }x\text{ }=\text{ }-\text{ }1/6\text{ }x2\text{ }\text{ }1/3\] \[1/6\text{ }x2\text{ }+\text{ }2/3\text{ }x\text{ }+\text{ }1/3\text{ }=\text{ }0\] Increasing by 6 on...
Solve equations using formula: 2×2 + 7x + 5 = 0
Given condition, \[2x2\text{ }+\text{ }7x\text{ }+\text{ }5\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }2,\text{ }b\text{ }=\text{ }7\text{ }and\text{ }c\text{ }=\text{ }5\] By quadratic equation,...
Solve equations using formula: 3×2 + 2x – 1 = 0
Given condition, \[3x2\text{ }+\text{ }2x\text{ }\text{ }1\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }3,\text{ }b\text{ }=\text{ }2\text{ }and\text{ }c\text{ }=\text{ }-\text{ }1\] By quadratic...
Solve equations using formula: x2 + 2x – 6 = 0
Given condition, \[x2\text{ }+\text{ }2x\text{ }\text{ }6\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }2\text{ }and\text{ }c\text{ }=\text{ }-\text{ }6\] By quadratic...
Solve equations using formula: x2 + 6x – 10 = 0
Given condition, \[x2\text{ }+\text{ }6x\text{ }\text{ }10\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }6\text{ }and\text{ }c\text{ }=\text{ }-\text{ }10\] By quadratic...
Solve using the formula: x2 – 10x + 21 = 0
Given condition, \[x2\text{ }\text{ }10x\text{ }+\text{ }21\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1\] , \[b\text{ }=\text{ }-\text{ }10\] and \[c\text{ }=\text{ }21\] By quadratic equation,...
Solve using the formula: x2 – 6x = 27
Given condition, \[~x2\text{ }\text{ }6x\text{ }=\text{ }27\] \[x2\text{ }\text{ }6x\text{ }\text{ }27\text{ }=\text{ }0\] Here, \[a\text{ }=\text{ }1\] , \[b\text{ }=\text{ }-\text{ }6\] and...