First term is \[\left( a \right)\text{ }=\text{ }1\] And, common ratio\[\left( r \right)\text{ }=\text{ }\surd 3/1\text{ }=\text{ }\surd 3\] We know that, the general term is \[{{t}_{n}}~=\text{...
Find the nth term of the series: 1, 2, 4, 8, ……..
It's seen that, the initial term is \[\left( a \right)\text{ }=\text{ }1\] What's more, typical ratio \[\left( r \right)\text{ }=\text{ }2/\text{ }1\text{ }=\text{ }2\] We realize that, the overall...
Find the 10th term of the G.P. :
Answer It can be written as \[12,\text{ }4,\text{ }4/3,\text{ }\ldots ..\] It's seen that, the initial term is \[\left( a \right)\text{ }=\text{ }12\] What's more, typical ratio \[\left( r...
Find the 8th term of the sequence:
Answer It's seen that, the initial term is \[\left( a \right)\text{ }=\text{ }1\] What's more, typical ratio \[\left( r \right)\text{ }=\text{ }\surd 3/1\text{ }=\text{ }\surd 3\] We realize that,...
Find the 9th term of the series: 1, 4, 16, 64, …..
It's seen that, the initial term is \[\left( a \right)\text{ }=\text{ }1\] What's more, typical ratio\[\left( r \right)\text{ }=\text{ }4/1\text{ }=\text{ }4\] We realize that, the overall term is...
Find which of the following sequence form a G.P.: 9, 12, 16, 24, ………
Given arrangement: \[9,\text{ }12,\text{ }16,\text{ }24,\text{ }\ldots ...\] Since, \[12/9\text{ }=\text{ }4/3;\text{ }16/12\text{ }=\text{ }4/3;\text{ }24/16\text{ }=\text{ }3/2\] \[12/9\text{...
Find which of the following sequence form a G.P.: (i) 8, 24, 72, 216, ……… (ii) 1/8, 1/24, 1/72, 1/216, ………
(i) Given arrangement:\[~8,\text{ }24,\text{ }72,\text{ }216,\text{ }\ldots \text{ }\ldots \] Since, \[24/8\text{ }=\text{ }3,\text{ }72/24\text{ }=\text{ }3,\text{ }216/72\text{ }=\text{ }3\]...