As per the given question,
Evaluate the following integrals: $\int{\frac{2x-3}{{{x}^{2}}+6x+13}dx}$
As per the given question,
Evaluate the following integrals:$\int{\frac{x-3}{{{x}^{2}}+2x-4}}dx$
As per the given question,
Evaluate the following integrals: $\int{\frac{x+1}{{{x}^{2}}+x+3}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{x}{{{x}^{2}}+3x+2}}dx$
As per the given question, We will solve \[{{I}_{1}}and\text{ }{{I}_{2}}\] individually.
Evaluate the following integrals: $\int{\frac{\cos 2x}{\sqrt{{{\sin }^{2}}2x+8}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{\sin 8x}{\sqrt{9+{{\sin }^{4}}4x}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{x\sqrt{4-9{{(\log x)}^{2}}}}}dx$
As per the given question,
Evaluate the following integrals: $\int{\frac{x}{\sqrt{4-{{x}^{4}}}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{\sin x}{\sqrt{4{{\cos }^{2}}x-1}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{\cos x}{\sqrt{4+{{\sin }^{2}}x}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{{{e}^{x}}}{\sqrt{16-{{e}^{2x}}}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{{{\sec }^{2}}x}{\sqrt{4+{{\tan }^{2}}x}}dx}$
As per the given question,
Evaluate the following integrals: \[\int{\frac{x}{\sqrt{{{x}^{4}}+{{a}^{4}}}}dx}\]
As per the given question,
Evaluate the following integrals: $\int{x\;{{e}^{2x}}}dx$
As per the given question,
Evaluate the following integrals: $\int{x\;{{e}^{x}}}dx$
As per the given question,
Evaluate the following integrals: $\int{{{x}^{3}}\;\log x\;dx}$
As per the given question,
Evaluate the following integrals: $\int{\log (x+1)dx}$
As per the given question,
Evaluate the following integrals:$\int{x\;\cos x\;dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{5\cos x+6}{2\cos x+\sin x+3}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{p+q\tan x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{3+2\cos x+4\sin x}{2\sin x+\cos x+3}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{1-\tan x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{1-\cot x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{1-\sin x+\cos x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{4\cos x-1}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{1-2\sin x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{5-4\sin x}}dx$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{5+4\cos x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{\cos x}{\cos 3x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{2}{2+\sin 2x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{4{{\sin }^{2}}x+5{{\cos }^{2}}x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{1}{4{{\cos }^{2}}x+9{{\sin }^{2}}x}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{3x+1}{\sqrt{5-2x-{{x}^{2}}}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{6x-5}{\sqrt{3{{x}^{2}}-5x+1}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{x+1}{\sqrt{4+5x-{{x}^{2}}}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{2x+1}{\sqrt{{{x}^{2}}+2x-1}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{x}{\sqrt{{{x}^{2}}+6x+10}}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{{{x}^{2}}}{{{x}^{2}}+7x+10}dx}$
As per the given question, Hence,
Evaluate the following integrals: $\int{\frac{{{x}^{2}}+1}{{{x}^{2}}-5x+6}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{(1-{{x}^{2}})}{x(1-2x)}dx}$
As per the given question,
Evaluate the following integrals: $\int{\frac{{{x}^{2}}+x-1}{{{x}^{2}}+x-6}dx}$
\[\Rightarrow ~1\text{ }=\text{ }\left( A\text{ }+\text{ }B \right)\text{ }x\text{ }+\text{ }\left( 3A\text{ }\text{ }2B \right)\] $⇒$ Then $A\;+\;B\;=\;0\;… (1)$ And $3A\;–\;2B\;=\;1\;… (2)$...
Evaluate the following integrals: $\int{\frac{{{x}^{2}}+x+1}{{{x}^{2}}-x}dx}$
As per the given question,
Evaluate: $\int \frac{x}{(x-3) \sqrt{x+1}} d x$
As per the given question,
Evaluate: $\int \frac{x^{2}}{(x-1) \sqrt{x+2}} d x$
As per the given question,
Evaluate: $\int \frac{x+1}{(x-1) \sqrt{x+2}} d x$
As per the given question,
Evaluate: $\int \frac{1}{(x-1) \sqrt{2 x+3}} d x$
As per the given question,
Evaluate: $\int \frac{1}{(x-1) \sqrt{x+2}} d x$
As per the given question,
Evaluate: $\int \frac{x^{2}-3 x+1}{x^{4}+x^{2}+1} d x$
As per the given question,
Evaluate: $\int \frac{1}{x^{4}+x^{2}+1} d x$
As per the given question, We get,
Evaluate: $\int \frac{x^{2}+9}{x^{4}+81} d x$
As per the given question,
Evaluate: $\int \sqrt{\cot \theta} \mathrm{d} \theta$
As per the given question, Now, substituting $t$ as $x – 1/x$ and $z$ as $x + 1/x$ we have
Evaluate: $\int \frac{x^{2}+1}{x^{4}+x^{2}+1} d x$
The given equation can be written as,
Evaluate: $\int \frac{x^{2}+1}{x^{2}-1} d x$
As per the given question,
Evaluate: $\int \frac{3+4 x-x^{2}}{(x+2)(x-1)} d x$
As per the given question:
Evaluate: $\int \frac{x^{2}+x-1}{x^{2}+x-6} d x$
As per the given question,
Evaluate: $\int \frac{1}{x(x-2)(x-4)} d x$
As per the given question,
Evaluate: $\int \frac{2 x+1}{(x+1)(x-2)} d x$
As per the given question,
Evaluate: $\int(x+2) \sqrt{x^{2}+x+1} d x$
As per the given question,
Evaluate: $\int(2 x-5) \sqrt{2+3 x-x^{2}} d x$
As per the given question,
Evaluate: $\int(x+1) \sqrt{2 x^{2}+3} d x$
As per the given question, Solution:
Evaluate: $\int(x+1) \sqrt{x^{2}-x+1} d x$
As per the given question,
Evaluate: $\int \cos x \sqrt{4-\sin ^{2} x} d x$
As per the given question,
Evaluate: $\int \sqrt{1+x-2 x^{2}} d x$
As per the given question,
Evaluate: $\int \sqrt{x-x^{2}} d x$
As per the given question,
Evaluate: $\int \sqrt{x^{2}+x+1} d x$
As per the given question,
Evaluate: $\int \sqrt{3+2 x-x^{2}} d x$
As per the given question,
Evaluate: $\int e^{2 x} \sin x \cos x d x$
As per the given question,
Evaluate: $\int e^{2 x} \cos (3 x+4) d x$
As per the given question,
Evaluate: $\int \cos (\log x) d x$
As per the given question,
Evaluate: $\int e^{a x} \sin (b x+c) d x$
As per the given question,
Evaluate: $\int e^{a x} \cos b x d x$
As per the given question,
Evaluate: $\int e^{x}\left(\frac{x-1}{2 x^{2}}\right) d x$
As per the given question,
Evaluate: $\int e^{x}\left(\cot x-\operatorname{cosec}^{2} x\right) d x$
As per the given question,
Evaluate: $\int e^{x}\left(\frac{1+\sin x}{1+\cos x}\right) d x$
Evaluate: $\int e^{x}\left(\frac{1}{x^{2}}-\frac{2}{x^{3}}\right) d x$
Evaluate: $\int e^{x}(\cos x-\sin x) d x$
$\int \frac{{x}^{7}}{\left(a^{2}-x^{2}\right)^{5}} d x$
Solution: $\mathrm{I}=\int \frac{x^{7}}{\left(a^{2}-x^{2}\right)^{5}} d x$ Suppose $\mathrm{x}=a \sin \theta$ On differentiating both the sides we obtain $d x=a \cos \theta d \theta$...
$\int \frac{x^{2}}{\left(a^{2}-x^{2}\right)^{\frac{3}{2}}} d x$
Solution: Given that $\int \frac{x^{2}}{\left(a^{2}-x^{2}\right)^{3 / 2}} d x$ Putting $x=a \sin \theta$, then $d x=a \cos \theta d \theta$ and $\theta=\sin ^{-1}(x / a)$ The above equation becomes,...
$\int \sin ^{3} x \cos ^{6} x d x$
Solution: As power of $\sin$ is odd, put $\cos x=t$ Therefore $\mathrm{dt}=-\sin \mathrm{x} \mathrm{d} \mathrm{x}$ On substitute these in above equation, we get $\begin{array}{l} \int \sin ^{3} x...
$\int \sin ^{5} x \cos x d x$
Solution: Assume $\sin x=t$ Therefore $\mathrm{d}(\sin \mathrm{x})=\mathrm{dt}=\cos \mathrm{x} \mathrm{dx}$ Putting $t=\sin x$ and $d t=\cos x d x$ in given equation, we get $\int \sin ^{5} x \cos x...
$\int \cos ^{5} x d x$
Solution: We can write the given question as $\begin{array}{l} \int \cos ^{5} x d x=\int \cos ^{3} x \cos ^{2} x d x \\ =\int^{\cos ^{3} x\left(1-\sin ^{2} x\right) d x}\left\{\text { since } \sin...
$\int \sin ^{5} x d x$
Solution: We can write the given equation as $\begin{array}{l} \int \sin ^{5} x d x=\int \sin ^{3} x \sin ^{2} x d x \\ =\int \sin ^{3} x\left(1-\cos ^{2} x\right) d x\left\{\text { since } \sin...
$\int \sin ^{4} x \cos ^{3} x d x$
Solution: Suppose $\sin x=t$ It is known that the Differentiation of $\sin x=\cos x$ $\mathrm{dt}=\mathrm{d}(\sin \mathrm{x})=\cos \mathrm{x} \mathrm{dx}$ $\mathrm{Therefore},...
Evaluate the following integrals:
$\int \sqrt{\tan x} \sec ^{4} x d x$
Solution: Assume $I=\int \sqrt{\tan x} \sec ^{4} x d x$ We can write the above equation as $\Rightarrow I=\int \sqrt{\tan x} \sec ^{2} x \sec ^{2} x d x$ Now, taking common $\begin{array}{l}...
Evaluate the following integrals:
$\int \tan ^{5} x d x$
Solution: Assume $I=\int \tan ^{5} x d x$ We can write the above equation as $\Rightarrow I=\int \tan ^{2} x \tan ^{3} x d x$ By using the standard formula $\Rightarrow I=\int\left(\sec ^{2}...
Evaluate the following integrals:
$\int \sec ^{6} x \tan x d x$
Solution: Assume $I=\int \sec ^{6} x \tan x d x$ We can write the above equation as $\Rightarrow I=\int \sec ^{5} x(\sec x \tan x) d x$ Substituting, $\sec x=t \Rightarrow \sec x \tan x d x=d t$, we...
Evaluate the following integrals:
$\int \tan ^{5} x \sec ^{4} x d x$
Solution: Assume $I=\int \tan ^{5} x \sec ^{4} x d x$ We can write the above equation as $\Rightarrow I=\int \tan ^{5} x \sec ^{2} x \sec ^{2} x d x$ Taking $\tan ^{5} \mathrm{x}$ as common, we get...
Evaluate the following integrals:
$\int \tan x \sec ^{4} x d x$
Solution: Assume $I=\int \tan x \sec ^{4} x d x$ We can write the above equation as $\Rightarrow \mathrm{I}=\int \tan \mathrm{x} \sec ^{2} \mathrm{x} \sec ^{2} \mathrm{x} \mathrm{dx}$...
Evaluate the following integrals:
$\int \tan ^{3} x \sec ^{2} x d x$
Solution: Assume $I=\int \tan ^{3} x \sec ^{2} x d x$ Assume $\tan \mathrm{x}=\mathrm{t}$, then $\Rightarrow \sec ^{2} x d x=d t$ On substituting the values of $x$, we get $\Rightarrow...
$\int\left(2 x^{2}+3\right) \sqrt{x+2} d x$
Solution: Assume $I=\int\left(2 x^{2}+3\right) \sqrt{x+2} d x$ Substituting $x+2=t \Rightarrow d x=d t$ On substituting the values of $x$ in given equation, we obtain $\begin{array}{l} \Rightarrow...
$\int \frac{2 x-1}{(x-1)^{2}} d x$
Solution: Assume $I=\int \frac{2 x-1}{(x-1)^{2}} d x$ Substituting $x-1=t \Rightarrow d x=d t$ On substituting the values of $x$, we get $\Rightarrow \mathrm{I}=\int...
$\int \frac{x^{2}}{\sqrt{3 x+4}} d x$
Solution: Assume $\mathrm{I}=\int \frac{\mathrm{x}^{2}}{\sqrt{3 \mathrm{x}+4}} \mathrm{dx}$ Substituting $3 x+4=t \Rightarrow 3 d x=d t$ By substituting the values of $x$, we get $\Rightarrow I=\int...
$\int \frac{{x}^{2}}{\sqrt{x-1}} d x$
Solution: Assume $I=\int \frac{x^{2}}{\sqrt{x-1}} d x$ By substituting $x-1=t \Rightarrow d x=d t$ On substituting the values we obtain $\Rightarrow \mathrm{I}=\int...
$\int x^{2} \sqrt{x+2} d x$
Solution: Assume $I=\int x^{2} \sqrt{x+2} d x$ By substituting, $x+2=t \Rightarrow d x=d t$ $\begin{array}{l} I=\int(t-2)^{2} \sqrt{t} d t \\ \Rightarrow I=\int\left(t^{2}-4 t+4\right) \sqrt{t} d t...
Evaluate the following integrals:
$\int \frac{1}{\sqrt{1-x^{2}}\left(\sin ^{-1} x\right)^{2}} d x$
Solution: Let $\sin ^{-1} \mathrm{x}=\mathrm{t}$ $\begin{array}{l} \Rightarrow \mathrm{d}\left(\sin ^{-1} \mathrm{x}\right)=\mathrm{d} \mathrm{t} \\ \Rightarrow...
Evaluate the following integrals:
$\int \frac{1+\sin x}{\sqrt{x-\cos x}} d x$
Solution: Let $x-\cos x=t$ $\begin{array}{l} \Rightarrow d(x-\cos x)=d t \\ \Rightarrow(1+\sin x) d x=d t \end{array}$ $\therefore$ By substituting $\mathrm{t}$ and dt in given equation we obtain...
Evaluate the following integrals:
$\int \frac{\left\{e^{\sin ^{-1} x}\right\}^{2}}{\sqrt{1-x^{2}}} d x$
Solution: Let $\sin ^{-1} \mathrm{x}=\mathrm{t}$ $\begin{array}{l} \Rightarrow \mathrm{d}\left(\sin ^{-1} \mathrm{x}\right)=\mathrm{dt} \\ \Rightarrow...
Evaluate the following integrals:
$\int \cot ^{3} x \operatorname{cosec}^{2} x d x$
Solution: Let $\cot x=t$ $\begin{array}{l} \Rightarrow \mathrm{d}(\cot x)=d t \\ \Rightarrow-\operatorname{cosec}^{2} x \cdot d x=d t \\ \Rightarrow d x=\frac{-d t}{\csc ^{2} x} \end{array}$...
Evaluate the following integrals:
$\int \frac{e^{x}}{\left(1+e^{x}\right)^{2}} d x$
Solution: Let $1+\mathrm{e}^{\mathrm{x}}=\mathrm{t}$ $\Rightarrow d\left(1+e^{x}\right)=d t$ $\Rightarrow \mathrm{e}^{\mathrm{x}} \mathrm{dx}=\mathrm{dt}$ $\therefore$ By substituting $t$ and $dt$...
Evaluate the following integrals:
$\int \sqrt[3]{\cos ^{2} x} \sin x d x$
Solution: Let $\cos x=t$ $\begin{array}{l} \Rightarrow \mathrm{d}(\cos x)=d t \\ \Rightarrow-\sin x d x=d t \\ \Rightarrow d x=\frac{-d t}{\sin x} \end{array}$ $\therefore$ On substituting...
Evaluate the following integrals:
$\int \sqrt{1+e^{x}} e^{x} d x$
Solution: Let $1+e^{x}=t$ $\begin{array}{l} \Rightarrow \mathrm{d}\left(1+\mathrm{e}^{\mathrm{x}}\right)=\mathrm{dt} \\ \Rightarrow \mathrm{e}^{\mathrm{x}} \mathrm{d} \mathrm{x}=\mathrm{d}...
Evaluate the following integrals:
$\int \frac{(1+\sqrt{x})^{2}}{\sqrt{x}} d x$
Solution: Let $1+v x=t$ $\begin{array}{l} \Rightarrow d(1+v x)=d t \\ \Rightarrow \frac{1}{2 \sqrt{x}} d x=d t \\ \Rightarrow \frac{1}{\sqrt{x}} d x=2 d t \end{array}$ $\therefore$ On substituting...
Evaluate the following integrals:
$\int \frac{\log \left(1+\frac{1}{x}\right)}{x(1+x)} d x$
Solution: Let $\log \left(1+\frac{1}{\mathrm{x}}\right)=\mathrm{t}$ $\begin{array}{l} \Rightarrow \operatorname{d}\left(\log \left(1+\frac{1}{\mathrm{x}}\right)\right)=\mathrm{dt} \\ \Rightarrow...
Evaluate the following integrals:
$\int \frac{\log x}{x} \mathrm{dx}$
Solution: Let $\log x=t$ $\begin{array}{l} \Rightarrow d(\log x)=d t \\ \Rightarrow \frac{1}{x} d x=d t \end{array}$ By substituting $\mathrm{t}$ and $dt$ in above equation we obtain...
Evaluate the following integrals:
$\int \frac{\sin (x-a)}{\sin (x-b)}$
Solution: It is better to eliminate the denominator, in order to solve these equations. $\Rightarrow \int \frac{\sin (x-a)}{\sin (x-b)} d x$ Now, add and subtract $b$ in $(x-a)$ $\begin{array}{l}...
Evaluate the following integrals:
$\int \frac{\cos 2 x}{(\cos x+\sin x)^{2}} d x$
Solution: Suppose $\mathrm{I}=\int \frac{\cos 2 x}{(\cos \mathrm{x}+\sin \mathrm{x})^{2}} d x$ On substituting the formula, we obtain $=\int \frac{\cos ^{2} x-\sin ^{2} x}{(\cos x+\sin x)^{2}} d x$...
Evaluate the following integrals:
$\int \frac{\sec x}{\sec 2 x} d x$
Solution: First of all we need to convert sec $x$ in terms of $\cos x$ It is known that $\Rightarrow \sec x=\frac{1}{\cos x}, \sec 2 x=\frac{1}{\cos 2 x}$ So, the above equation becomes,...
Evaluate the following integrals:
$\int \frac{\sqrt{1-\cos x}}{\sqrt{1+\cos x}} d x$
Solution: Given that, $\int \frac{\sqrt{1-\cos x}}{\sqrt{1+\cos x}} d x$ It is known that $\begin{array}{l} 1-\operatorname{Cos} x=2 \sin ^{2} \frac{x}{2} \\ 1+\cos x=2 \cos ^{2} \frac{x}{2}...
Solve: $\int \frac{1}{\sqrt{3 x^{2}+5 x+7}} d x$
As per the question suggests,
Evaluate the following integrals:
$\int \frac{\sqrt{1+\cos 2 x}}{\sqrt{1-\cos 2 x}} d x$
Solution: Given that, $\int \frac{\sqrt{1+\cos 2 x}}{\sqrt{1-\cos 2 x}} d x$ It is known that $\begin{array}{l} 1+\cos 2 x=2 \cos ^{2} x \\ 1-\cos 2 x=2 \sin ^{2} x \end{array}$ On substituting...
Evaluate the following integrals:
$\int \frac{1}{\sqrt{1-\cos 2 x}} d x$
Solution: Given that $\int \frac{1}{\sqrt{1-\cos 2 x}} d x$ In the equation given $\cos 2 x=\cos ^{2} x-\sin ^{2} x$ Also it is known that $\cos ^{2} x+\sin ^{2} x=1$ On substituting the values in...
Solve: $\int \frac{1}{\sqrt{5-4 x-2 x^{2}}} d x$
As per the question suggests,
Solve: $\int \frac{1}{\sqrt{8+3 x-x^{2}}} d x$
As per the question suggests,
Solve: $\int \frac{1}{\sqrt{2 x-x^{2}}} d x$
As per the question suggests,
Solve: $\int \frac{e^{3 x}}{4 e^{6 x}-9} d x$
As per the question suggests,
Solve: $\int \frac{e^{x}}{e^{2 x}+5 e^{x}+6} d x$
As per the question suggests,
Solve: $\int \frac{\cos x}{\sin ^{2} x+4 \sin x+5} d x$
As per the question suggests,
$\int \cos m x \cos n x d x, m \neq n$
As per the given question,
Solve:$\int \frac{e^{x}}{1+e^{2 x}} d x$
As per the question suggets,
$\int \cos 3 x \cos 4 x d x$
As per the given question,
$\int \sin 4 x \cos 7 x d x$
As per the given question,
Solve:$\int \frac{\sec ^{2} x}{1-\tan ^{2} x} d x$
As per the question suggests,
$\int \sin ^{2} b x d x$
As per the given question,
$\int \cos ^{4} 2 x d x$
As per the given question,
$\int \sin ^{3}(2 x+1) d x$
As per the given question,
$\int \sin ^{2}(2 x+5) d x$
As per the given question,
$\int \frac{2 x+1}{\sqrt{3 x+2}} d x$
As per the given questions,
$\int(x+2) \sqrt{3 x+5} d x$
As per the given question,
Solve: $\int \frac{1}{x^{2}+6 x+13} d x$
As per the question,
$\int \frac{x-1}{\sqrt{x+4}} d x$
As per the given question,
Solve: $\int \frac{1}{2 x^{2}-x-1} d x$
As per the question suggests,
$\int x \sqrt{x+2} d x$
As per the given question,
$\int \frac{x+1}{\sqrt{2 x+3}} d x$
As per the given question,
Solve: $\int \frac{1}{1+x-x^{2}} d x$
As per the question suggests, By using,
Solve: $\int \frac{1}{x^{2}-10 x+34} d x$
As per the question suggests,
$\int \frac{x^{2}+x+5}{3 x+2} d x$
As per the given question,
$\int \frac{x^{3}}{x-2} d x$
As per the given question,
$\int \frac{x^{2}+5 x+2}{x+2} d x$
Solution: As per the given question:
Solve: $\int \frac{1}{4 x^{2}+12 x+5} d x$
As per the question suggests,
Solve: $\int \frac{1}{\sqrt{1+4 x^{2}}} d x$
As per the question suggests,
Solve: $\int \frac{x^{2}-1}{x^{2}+4} d x$
as per the question suggestion,
Solve: $\int \frac{1}{a^{2} x^{2}+b^{2}} d x$
as per the question suggests,
Solve: $\int \frac{1}{a^{2} x^{2}-b^{2}} d x$
as per the question suggests,
Solve: $\int \frac{1}{a^{2}-b^{2} x^{2}} d x$
As per the question suggests,
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
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Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following Integral:
Answer: According to the question, the given integral can be solved as
Evaluate the following integral:
Answer: According to the question the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate the following integral:
Answer:- According to question, the given integral can be solved as
Evaluate:
Answer:- According to question, the given integrals can be solved as (i) (ii)
Evaluate the following integrals:
(i) (ii) Answer:- According to question, the given integrals can be solved as (i) (ii)
Evaluate the following integrals:
(i) (ii) Answer:- According to question, the given integrals can be solved as (i) (ii)
Evaluate the following integrals:
(i) (ii) Answer: According to question, the given integrals can be solved as (i) (ii)
Evaluate the following integrals:
Answer: Given, According to question, the given integrals can be solved as (i) (ii)